Rank

The rank of a matrix is the number of pivots and the number of dimensions that the column space of a matrix occupies.


Rank and Dimension

A matrix with n dimensions exists in Rn space. However, the column space of that same matrix does not necessarily exist in the same number of dimensions.

Consider a matrix A like:

┌      ┐
│ 1 2 3│
│ 1 3 4│
│ 1 4 5│
└      ┘

The third column vector can be trivially shown to not be independent; it is a sum of the first and second column vectors. Correspondingly, the eliminated form of the matrix has two pivots and a free variable. As a direct consequence of this being a square matrix (n x n), this also means that there are two pivot rows and a zero row.

┌         ┐
│ [1] 2  3│
│  0 [1] 1│
│  0  0  0│
└         ┘

A is not a basis for R3 space. The requirements for a basis are that each column be independent and that the matrix span all dimensions.

However, this matrix does contain two independent columns. If those are split off like:

┌    ┐
│ 1 2│
│ 1 3│
│ 1 4│
└    ┘

Then this new matrix is a basis for the column space of A (sometimes notated as C(A)), which happens to be 2 dimensional.

Effectively, this matrix expresses a 2-dimensional plane that exists within a 3-dimensional space, but it is bound to that plane and cannot vary across the third dimension.


Categories for Solutions

If a matrix has a pivot in each column, it is said to be full column rank. The only null space is the zero vector (i.e. [0 ...]). Ax = b either has one solution or is not solvable. Incidentally, the reduced row echelon form (R) looks like the identity matrix (I) with some number of zero rows.

If a matrix has a pivot in each row, it is said to be full row rank. This only means that Ax = b can be solved for any b.

If a square matrix has full rank, the reduced row echelon form (R) of the matrix is the identity matrix (I). The only null space is the zero vector; Ax = b can be solved for any b; there is exactly one solution for any given b.

If a matrix is none of the above, Ax = b either can be solved for any b or is not solvable.


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LinearAlgebra/Rank (last edited 2024-03-12 15:07:54 by DominicRicottone)