Differences between revisions 1 and 19 (spanning 18 versions)
Revision 1 as of 2023-07-08 18:05:18
Size: 2152
Comment:
Revision 19 as of 2026-01-21 02:49:15
Size: 2465
Comment: Rank-nullity theorem
Deletions are marked like this. Additions are marked like this.
Line 1: Line 1:
= Null Spaces = = Null Space =
Line 3: Line 3:
The '''null space''' of a system of equations is the set of solutions for which the dependent variables 'cancel out'. In other words, all values of ''x'' such that ''Ax = 0''. A '''null space''' is a particular category of '''subspaces'''. The '''null space''' of a system of equations is the set of solutions for which the dependent variables cancel out.
Line 11: Line 11:
== Utility == == Definition ==
Line 13: Line 13:
Defining the null space of a system is useful for defining the '''complete solution'''. In linear algebra, the '''null space''' is the subspace that satisfies '''''A'''x = 0''. It is notated as ''N('''A''')''.
Line 15: Line 15:
Algebraically, null spaces have an identity property. Given any valid solution to ''Ax = b'', ''any'' combination of null spaces can be added to that solution to create another valid solution, because ''b + 0 = b''. Null spaces are composed of null space vectors. There is always a '''zero vector''' in the null space. If a matrix is [[LinearAlgebra/Invertibility|invertible]] however, the zero vector is the ''only'' null space vector.

The number of dimensions spanned by the null space vectors is called '''nullity''', and it has a direct relation to [[LinearAlgebra/Rank|rank]]. For any matrix '''''A''''' of size ''m x n'' (i.e., there are ''n'' columns), ''rank('''A''') + nullity('''A''') = n''.

Null space vectors have an identity property. Given any valid solution to '''''A'''x = b'', ''any'' combination of null spaces can be added to that solution to create another valid solution, because ''b + 0 = b''.
Line 21: Line 25:
== Solving == == Solutions ==
Line 23: Line 27:
Given an [[LinearAlgebra/Elimination|eliminated]] matrix, the solution for null space begins with identifying the '''free columns'''. Leaving aside the invertible case, the non-zero vectors of the null space can be solved for.
Line 25: Line 29:
Null spaces will follow a pattern:

 * There will be a null space for each free column.
 * Populate each vector with the corresponding free column position holding a one, and all other free column positions holding a zero.
 * Solve the system of equation given these values and given a right hand side value of 0.

As an example, consider this system:
Consider the below system of equations.
Line 34: Line 32:
w + 2x + 2y + 2z = a
2w + 4x + 6y + 8z = b
3w + 6x + 8y + 10z = c
w + 2x + 2y + 2z = 1
2w + 4x + 6y + 8z = 5
3w + 6x + 8y + 10z = 6
Line 39: Line 37:
This is eliminated into the following augmented matrix: This system is formulated as a matrix and eliminated into:
Line 42: Line 40:
┌ ┐
│ [1] 2 2 2 a│
│ 0 0 [2] 4 b-2a│
│ 0 0 0 0 c-b-a│
└ ┘
┌ ┐ ┌ ┐ ┌ ┐
│[1] 2 2 2│ │ w│ │ 1│
│ 0 0 [2] 4│ │ x│ = │ 3│
│ 0 0 0 0│ │ y│ │ 0│
└ ┘ │ z│ └ ┘
              └ ┘
Line 49: Line 48:
The free columns are 2 and 4. Therefore, the null space solutions begin like: The number of vectors in the null space match the number of free variables. In this case, there are 2.
Line 51: Line 50:
{{{
[ ? 1 ? 0 ]
[ ? 0 ? 1 ]
}}}
The null space vectors can be 'prepopulated' or 'templated' by allowing pivot variables to vary and alternating which free variable is set to 0 or 1. In this case, they are:
 * ''[w 1 y 0]''
 * ''[w 0 y 1]''
Line 56: Line 54:
The first solution can be found by rewriting the first equation from the system (with 0 as the right hand value): Solve '''''A'''x = 0'' using these values. For example, substituting in the first vector's values gives...
Line 63: Line 61:
}}}
Line 65: Line 62:
Substitute this into the second equation:

{{{
Line 70: Line 64:
2w + 4 + 6y = 0
Line 75: Line 71:
}}}
Line 77: Line 72:
Substitute this into the first equation again:

{{{
Line 85: Line 77:
The first null space solution is: ...a null space vector in ''[-2 1 0 0]''.
Line 87: Line 79:
{{{
[-2 1 0 0]
}}}

Repeat the process for the second solution, arriving at:

{{{
[2 0 -1 1]
}}}
The second null space vector is ''[2 0 -1 1]''.

Null Space

A null space is a particular category of subspaces. The null space of a system of equations is the set of solutions for which the dependent variables cancel out.


Definition

In linear algebra, the null space is the subspace that satisfies Ax = 0. It is notated as N(A).

Null spaces are composed of null space vectors. There is always a zero vector in the null space. If a matrix is invertible however, the zero vector is the only null space vector.

The number of dimensions spanned by the null space vectors is called nullity, and it has a direct relation to rank. For any matrix A of size m x n (i.e., there are n columns), rank(A) + nullity(A) = n.

Null space vectors have an identity property. Given any valid solution to Ax = b, any combination of null spaces can be added to that solution to create another valid solution, because b + 0 = b.


Solutions

Leaving aside the invertible case, the non-zero vectors of the null space can be solved for.

Consider the below system of equations.

w + 2x + 2y + 2z = 1
2w + 4x + 6y + 8z = 5
3w + 6x + 8y + 10z = 6

This system is formulated as a matrix and eliminated into:

┌           ┐ ┌  ┐   ┌  ┐
│[1] 2  2  2│ │ w│   │ 1│
│ 0  0 [2] 4│ │ x│ = │ 3│
│ 0  0  0  0│ │ y│   │ 0│
└           ┘ │ z│   └  ┘
              └  ┘

The number of vectors in the null space match the number of free variables. In this case, there are 2.

The null space vectors can be 'prepopulated' or 'templated' by allowing pivot variables to vary and alternating which free variable is set to 0 or 1. In this case, they are:

  • [w 1 y 0]

  • [w 0 y 1]

Solve Ax = 0 using these values. For example, substituting in the first vector's values gives...

w + 2x + 2y + 2z = 0
w + 2(1) + 2y + 2(0) = 0
w + 2 + 2y = 0
w = -2 - 2y

2w + 4x + 6y + 8z = 0
2w + 4(1) + 6y + 8(0) = 0
2w + 4 + 6y = 0

2w + 4 + 6y = 0
2(-2 - 2y) + 4 + 6y = 0
-4 - 4y + 4 + 6y = 0
2y = 0
y = 0

w = -2 - 2y
w = -2 - 2(0)
w = -2

...a null space vector in [-2 1 0 0].

The second null space vector is [2 0 -1 1].


CategoryRicottone

LinearAlgebra/NullSpace (last edited 2026-02-08 19:00:35 by DominicRicottone)