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← Revision 12 as of 2026-02-04 04:32:14 ⇥
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| A consistent linear system has either one or infinitely many solutions. The general solution describes all of them. | A consistent linear system has either one or infinitely many solutions. The '''general solution''' describes all of them. |
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| A complete solution is formalized as ''x,,c,, = x,,p,, + x,,0,,''. That is, the [[LinearAlgebra/NullSpace#Solution|null space]] must be solved and added to the [[LinearAlgebra/ParticularSolution|particular solution]]. The key is that any combination of the null space vectors can be added to a particular solution and give a new particular solution, because they have an identity property. |
A complete solution is formalized as ''x,,c,, = x,,p,, + x,,0,,''. That is, the [[LinearAlgebra/Basis|basis]] of the [[LinearAlgebra/NullSpace#Solution|null space]] must be identified, and linear combinations of it must be added to the [[LinearAlgebra/ParticularSolution|particular solution]]. Since all such combinations evaluate to 0, they have an identity property. |
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| Furthermore, it was noted [[LinearAlgebra/NullSpace#Solutions|here]] that the null space vectors are ''[-2 1 0 0]'' and ''[2 0 -2 1]''. The null space solution is ''any'' linear combination of these vectors. Consider: | Furthermore, it was noted [[LinearAlgebra/NullSpace#Solutions|here]] that a [[LinearAlgebra/Basis|basis]] for the null space is ''{[-2 1 0 0], [2 0 -2 1]}''. The null space solution is ''any'' linear combination of these vectors. Consider: |
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| {{{ ┌ ┐ ┌ ┐ │ -2 │ │ 2 │ x = C │ 1 │ + C │ 0 │ 0 1│ 0 │ 2│ -2 │ │ 0 │ │ 1 │ └ ┘ └ ┘ }}} |
{{attachment:null.svg}} |
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| Altogether, the complete solution for the second example above is: | Altogether, the complete solution for the second example above is ''x,,c,, = x,,p,, + x,,0,,''. |
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| {{{ x = x + x c p 0 |
{{attachment:complete.svg}} |
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| ┌ ┐ ┌ ┐ ┌ ┐ │ -2 │ │ -2 │ │ 2 │ x = │ 0 │ + C │ 1 │ + C │ 0 │ c │ 3/2│ 1│ 0 │ 2│ -2 │ │ 0 │ │ 0 │ │ 1 │ └ ┘ └ ┘ └ ┘ }}} |
---- == Row Space Solution == An alternative strategy follows from calculating a particular solution and the null space. Next, [[LinearAlgebra/Projection|project]] the particular solution onto the null space. The projection is notated ''x,,n,,''. The given particular solution can be related to that projection as ''x,,p,, = x,,r,, + x,,n,,''. This should look similar to the formulation of a complete solution; there is a component spanning row space, and there is a another spanning null space. But the minimum [[LinearAlgebra/Norm|norm]] particular solution does not move through the null space at all. So, evaluate ''x,,r,, = x,,p,, - x,,n,,'' to arrive at the '''row space solution'''. The optimized complete solution is ''x,,c,, = x,,r,, + c x,,n,,''. |
General Solution
A complete solution is a generalization of a particular solution. It is generally notated as xc.
Description
A consistent linear system has either one or infinitely many solutions. The general solution describes all of them.
A complete solution is formalized as xc = xp + x0. That is, the basis of the null space must be identified, and linear combinations of it must be added to the particular solution. Since all such combinations evaluate to 0, they have an identity property.
Solution
Consider the system:
w + 2x + 2y + 2z = 1 2w + 4x + 6y + 8z = 5 3w + 6x + 8y + 10z = 6
It was noted here that a particular solution is [-2 0 3/2 0].
Furthermore, it was noted here that a basis for the null space is {[-2 1 0 0], [2 0 -2 1]}. The null space solution is any linear combination of these vectors. Consider:
Altogether, the complete solution for the second example above is xc = xp + x0.
Row Space Solution
An alternative strategy follows from calculating a particular solution and the null space. Next, project the particular solution onto the null space. The projection is notated xn.
The given particular solution can be related to that projection as xp = xr + xn. This should look similar to the formulation of a complete solution; there is a component spanning row space, and there is a another spanning null space. But the minimum norm particular solution does not move through the null space at all. So, evaluate xr = xp - xn to arrive at the row space solution.
The optimized complete solution is xc = xr + c xn.
