= Antiderivative =

An '''antiderivative''' is the inverse of a [[Calculus/Derivative|derivative]].

<<TableOfContents>>

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== Rules ==

The basic rules/identities are:

||'''Rule'''                    ||'''Formulation'''         ||'''Defined for...'''||
||logarithms                    ||{{attachment:log.svg}}    || ||
||exponentiation                ||{{attachment:exp.svg}}    || ||
||exponentiation with a multiple||{{attachment:expmult.svg}}|| ||
||exponentiation (generalized)  ||{{attachment:expgen.svg}} || ||
||polynomials                   ||{{attachment:poly.svg}}   ||''n != -1'' (see the logarithm antiderivative in this case)||
||constants                     ||{{attachment:const.svg}}  || ||
||constant multiple             ||{{attachment:mult.svg}}   || ||

For [[Calculus/Trigonometry|trigonometric functions]]:

||'''Rule'''     ||'''Formulation'''        ||'''Defined for...'''||
||sine           ||{{attachment:sin.svg}}   || ||
||cosine         ||{{attachment:cos.svg}}   || ||
||secant squared ||{{attachment:sec2.svg}}  || ||



=== U-Substitution ===

Given a compound function to integrate, let ''u'' be the inner function. The integral can be solved by converting into terms of ''u'' and ''du''.

Consider the generalized exponentiation antiderivative rule. Given ''∫e^f(x)^dx'' to integrate, let ''u = f(x)''. The first derivative of ''u'' is ''f ' '', so ''du = f ' dx''. By factoring this out of the outer function and substituting it for ''du'', the integral is converted. See the final calculation above.

If solving a definite integral, note that the bounds must also be recalculated as ''a* = f(a)'' and ''b* = f(b)''.



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CategoryRicottone