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== Finite Fields ==

A non-obvious example of a field is the set ''{0,1}'' for which addition is defined ''(a + b) % 2'' and for which multiplication is defined ''(ab) % 2''. Because of the modulus, every possible arithmatic operation is:

 * ''0 + 0 = 0''
 * ''0 + 1 = 1''
 * ''1 + 1 = 0''
 * ''0 × 0 = 0''
 * ''0 × 1 = 0''
 * ''1 × 1 = 1''

The invertibility property of multiplication is the trickiest to satisfy, but due to the modulus, the inverse of 1 is in fact 0. (Recall that 0 is not required to have an inverse.)

Consider then the set ''{0,1,2}'' where addition is defined ''(a + b) % 3'' and for which multiplication is defined ''(ab) % 3''. It follows that ''1 × 1 = 1'' and ''2 × 2 = 1'', satisfying the invertibility property of multiplication again.

A '''finite field''' can be defined by the integers with any prime modulus. They are usually notated ''Z,,p,,'' or ''F,,p,,'' where ''p'' is the modulus.

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Fields

Fields are sets that are closed under addition and multiplication.


Description

A field is a set for which a pair of binary operations are defined: addition and mutliplication.

The field must be closed under both operations; that is, addition is a map as F + F -> F and multiplication is a map as F × F -> F.

The addition operation must also feature these properties:

  • commutivity: a + b = b + a

  • associativity: (a + b) + c = a + (b + c)

  • There exists a value satisfying an identity property: a + 0 = a.

  • invertibility: a + (-a) = 0

The multiplication operation must also feature these properties:

  • commutivity: ab = ba

  • associativity: (ab)c = a(bc)

  • There exists a value satisfying an identity property: a1 = a.

  • invertibility: Formally, because zero is excluded, it is said that ∀ a ∈ F \ {0} aa-1 = 1.

Lastly there js a distributivity property: (a + b)c = ac + bc.


Finite Fields

A non-obvious example of a field is the set {0,1} for which addition is defined (a + b) % 2 and for which multiplication is defined (ab) % 2. Because of the modulus, every possible arithmatic operation is:

  • 0 + 0 = 0

  • 0 + 1 = 1

  • 1 + 1 = 0

  • 0 × 0 = 0

  • 0 × 1 = 0

  • 1 × 1 = 1

The invertibility property of multiplication is the trickiest to satisfy, but due to the modulus, the inverse of 1 is in fact 0. (Recall that 0 is not required to have an inverse.)

Consider then the set {0,1,2} where addition is defined (a + b) % 3 and for which multiplication is defined (ab) % 3. It follows that 1 × 1 = 1 and 2 × 2 = 1, satisfying the invertibility property of multiplication again.

A finite field can be defined by the integers with any prime modulus. They are usually notated Zp or Fp where p is the modulus.


Commutative Rings

There are many sets which satisfy some but not all properties of a field. For example, the set of integers does not contain multiplicative inverses. It is instead a commutative ring.


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Analysis/Fields (last edited 2026-02-16 04:24:44 by DominicRicottone)